3.237 \(\int \frac {\cos ^m(c+d x)}{(b \cos (c+d x))^{4/3}} \, dx\)

Optimal. Leaf size=83 \[ \frac {3 \sin (c+d x) \cos ^m(c+d x) \, _2F_1\left (\frac {1}{2},\frac {1}{6} (3 m-1);\frac {1}{6} (3 m+5);\cos ^2(c+d x)\right )}{b d (1-3 m) \sqrt {\sin ^2(c+d x)} \sqrt [3]{b \cos (c+d x)}} \]

[Out]

3*cos(d*x+c)^m*hypergeom([1/2, -1/6+1/2*m],[5/6+1/2*m],cos(d*x+c)^2)*sin(d*x+c)/b/d/(1-3*m)/(b*cos(d*x+c))^(1/
3)/(sin(d*x+c)^2)^(1/2)

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Rubi [A]  time = 0.03, antiderivative size = 83, normalized size of antiderivative = 1.00, number of steps used = 2, number of rules used = 2, integrand size = 21, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.095, Rules used = {20, 2643} \[ \frac {3 \sin (c+d x) \cos ^m(c+d x) \, _2F_1\left (\frac {1}{2},\frac {1}{6} (3 m-1);\frac {1}{6} (3 m+5);\cos ^2(c+d x)\right )}{b d (1-3 m) \sqrt {\sin ^2(c+d x)} \sqrt [3]{b \cos (c+d x)}} \]

Antiderivative was successfully verified.

[In]

Int[Cos[c + d*x]^m/(b*Cos[c + d*x])^(4/3),x]

[Out]

(3*Cos[c + d*x]^m*Hypergeometric2F1[1/2, (-1 + 3*m)/6, (5 + 3*m)/6, Cos[c + d*x]^2]*Sin[c + d*x])/(b*d*(1 - 3*
m)*(b*Cos[c + d*x])^(1/3)*Sqrt[Sin[c + d*x]^2])

Rule 20

Int[(u_.)*((a_.)*(v_))^(m_)*((b_.)*(v_))^(n_), x_Symbol] :> Dist[(b^IntPart[n]*(b*v)^FracPart[n])/(a^IntPart[n
]*(a*v)^FracPart[n]), Int[u*(a*v)^(m + n), x], x] /; FreeQ[{a, b, m, n}, x] &&  !IntegerQ[m] &&  !IntegerQ[n]
&&  !IntegerQ[m + n]

Rule 2643

Int[((b_.)*sin[(c_.) + (d_.)*(x_)])^(n_), x_Symbol] :> Simp[(Cos[c + d*x]*(b*Sin[c + d*x])^(n + 1)*Hypergeomet
ric2F1[1/2, (n + 1)/2, (n + 3)/2, Sin[c + d*x]^2])/(b*d*(n + 1)*Sqrt[Cos[c + d*x]^2]), x] /; FreeQ[{b, c, d, n
}, x] &&  !IntegerQ[2*n]

Rubi steps

\begin {align*} \int \frac {\cos ^m(c+d x)}{(b \cos (c+d x))^{4/3}} \, dx &=\frac {\sqrt [3]{\cos (c+d x)} \int \cos ^{-\frac {4}{3}+m}(c+d x) \, dx}{b \sqrt [3]{b \cos (c+d x)}}\\ &=\frac {3 \cos ^m(c+d x) \, _2F_1\left (\frac {1}{2},\frac {1}{6} (-1+3 m);\frac {1}{6} (5+3 m);\cos ^2(c+d x)\right ) \sin (c+d x)}{b d (1-3 m) \sqrt [3]{b \cos (c+d x)} \sqrt {\sin ^2(c+d x)}}\\ \end {align*}

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Mathematica [A]  time = 0.10, size = 82, normalized size = 0.99 \[ -\frac {\sqrt {\sin ^2(c+d x)} \csc (c+d x) \cos ^{m+1}(c+d x) \, _2F_1\left (\frac {1}{2},\frac {1}{2} \left (m-\frac {1}{3}\right );\frac {1}{2} \left (m+\frac {5}{3}\right );\cos ^2(c+d x)\right )}{d \left (m-\frac {1}{3}\right ) (b \cos (c+d x))^{4/3}} \]

Antiderivative was successfully verified.

[In]

Integrate[Cos[c + d*x]^m/(b*Cos[c + d*x])^(4/3),x]

[Out]

-((Cos[c + d*x]^(1 + m)*Csc[c + d*x]*Hypergeometric2F1[1/2, (-1/3 + m)/2, (5/3 + m)/2, Cos[c + d*x]^2]*Sqrt[Si
n[c + d*x]^2])/(d*(-1/3 + m)*(b*Cos[c + d*x])^(4/3)))

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fricas [F]  time = 0.64, size = 0, normalized size = 0.00 \[ {\rm integral}\left (\frac {\left (b \cos \left (d x + c\right )\right )^{\frac {2}{3}} \cos \left (d x + c\right )^{m}}{b^{2} \cos \left (d x + c\right )^{2}}, x\right ) \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^m/(b*cos(d*x+c))^(4/3),x, algorithm="fricas")

[Out]

integral((b*cos(d*x + c))^(2/3)*cos(d*x + c)^m/(b^2*cos(d*x + c)^2), x)

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giac [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (d x + c\right )^{m}}{\left (b \cos \left (d x + c\right )\right )^{\frac {4}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^m/(b*cos(d*x+c))^(4/3),x, algorithm="giac")

[Out]

integrate(cos(d*x + c)^m/(b*cos(d*x + c))^(4/3), x)

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maple [F]  time = 0.07, size = 0, normalized size = 0.00 \[ \int \frac {\cos ^{m}\left (d x +c \right )}{\left (b \cos \left (d x +c \right )\right )^{\frac {4}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(d*x+c)^m/(b*cos(d*x+c))^(4/3),x)

[Out]

int(cos(d*x+c)^m/(b*cos(d*x+c))^(4/3),x)

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maxima [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos \left (d x + c\right )^{m}}{\left (b \cos \left (d x + c\right )\right )^{\frac {4}{3}}}\,{d x} \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)^m/(b*cos(d*x+c))^(4/3),x, algorithm="maxima")

[Out]

integrate(cos(d*x + c)^m/(b*cos(d*x + c))^(4/3), x)

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mupad [F]  time = 0.00, size = -1, normalized size = -0.01 \[ \int \frac {{\cos \left (c+d\,x\right )}^m}{{\left (b\,\cos \left (c+d\,x\right )\right )}^{4/3}} \,d x \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

int(cos(c + d*x)^m/(b*cos(c + d*x))^(4/3),x)

[Out]

int(cos(c + d*x)^m/(b*cos(c + d*x))^(4/3), x)

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sympy [F]  time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {\cos ^{m}{\left (c + d x \right )}}{\left (b \cos {\left (c + d x \right )}\right )^{\frac {4}{3}}}\, dx \]

Verification of antiderivative is not currently implemented for this CAS.

[In]

integrate(cos(d*x+c)**m/(b*cos(d*x+c))**(4/3),x)

[Out]

Integral(cos(c + d*x)**m/(b*cos(c + d*x))**(4/3), x)

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